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Home/ Questions/Q 6920807
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T10:11:43+00:00 2026-05-27T10:11:43+00:00

I’ve got two arrays in my bash, each containing files. In my loop, sometimes

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I’ve got two arrays in my bash, each containing files. In my loop, sometimes a file gets deleted. Whenever that happens, one of the arrays shows the old state, the other one shows the new state. How do I manage to show the difference between them, e. g. which file exactly got deleted? By the way, there is no other way to find out.

Here’s an example:

arr_a=( file1.txt file2.txt file3.txt )
arr_b=( file1.txt file3.txt )

#Now the output should be file2.txt

I imagined something lile echo ${arr_a[@]#arr_b[@]}, but this didn’t work. (This results in arr_a being output entirely.)

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T10:11:44+00:00Added an answer on May 27, 2026 at 10:11 am

    This one is a bit complicated but will work in the case the arrays don’t maintain correlativity. It sorts all elements of the larger array to correlate to those in the shorter array, and then prints the remaining elements in the larger array (it works on copies of the arrays). Not fully tested:

    #!/bin/bash
    arr_a=( file1.txt file2.txt file3.txt )
    arr_b=( file1.txt file3.txt )
    
    sortarr() {
        local sorted=( ${!1} ) sortby=( ${!2} )
        local length=${#sorted[@]} i=${#sortby} matches
        while (( i-- )); do
            [[ ! "${sorted[@]}" =~ ${sortby[$i]} ]] && continue
            sorted=( ${sorted[@]//$BASH_REMATCH/} )
            printf -v matches '%*s' $(( $length - ${#sorted[@]} ))
            sorted=( ${matches// /$BASH_REMATCH }${sorted[@]} )
        done
        for (( i=${#sortby[@]}; i<${#sorted[@]}; i++ )); do
            echo ${sorted[$i]}
        done
    }
    
    if (( ${#arr_a[@]} > ${#arr_b[@]} )); then
        sortarr arr_a[@] arr_b[@]
    else
        sortarr arr_b[@] arr_a[@]
    fi
    
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