Question

I’ve got two List<Name>s:

public class Name
        {
            public string NameText {get;set;}
            public Gender Gender { get; set; }
        }

public class Gender
        {
            public decimal MaleFrequency { get; set; }
            public decimal MaleCumulativeFrequency { get; set; }
            public decimal FemaleCumulativeFrequency { get; set; }
            public decimal FemaleFrequency { get; set; }
        }

If the NameText property matches, I’d like to take the FemaleFrequency and FemaleCumulativeFrequency from the list of female Names and the MaleFrequency and MaleCumulativeFrequency values from the list of male Names and create one list of Names with all four properties populated.

What’s the easiest way to go about this in C# using .Net 3.5?

Answer 1

Are you attempting to sum each of the values when you merge the lists? If so, try something like this:

List<Name> list1 = new List<Name>();
List<Name> list2 = new List<Name>();

List<Name> result = list1.Union(list2).GroupBy(x => x.NameText).Select(x => new
Name
{
    NameText = x.Key,
    Gender = new Gender
    {
        FemaleCumulativeFrequency = x.Sum(y => y.Gender.FemaleCumulativeFrequency),
        FemaleFrequency = x.Sum(y => y.Gender.FemaleFrequency),
        MaleCumulativeFrequency = x.Sum(y => y.Gender.MaleCumulativeFrequency),
        MaleFrequency = x.Sum(y => y.Gender.MaleFrequency)
    }
}).ToList();

What this does is the following:

1. Unions the lists, creating an IEnumerable<Name> that contains the contents of both lists.
2. Groups the lists by the NameText property, so if there are duplicate Names with the same NameText, they’ll show up in the same group.
3. Selects a set of new Name objects, with each grouped Name’s properties summed… you can also use Average if that makes more sense.
4. Converts the entire query to a List<Name> by calling the “ToList()” method.

Edit: Or, as you’ve said below, you simply want to merge the two lists… do this:

List<Name> allNames = femaleNames.Union(maleNames).ToList();