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Home/ Questions/Q 6091527
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T12:20:18+00:00 2026-05-23T12:20:18+00:00

I’ve grown fond of using a generator-like pattern between functions in my shell scripts.

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I’ve grown fond of using a generator-like pattern between functions in my shell scripts. Something like this:

parse_commands /da/cmd/file | process_commands

However, the basic problem with this pattern is that if parse_command encounters an error, the only way I have found to notify process_command that it failed is by explicitly telling it (e.g. echo “FILE_NOT_FOUND”). This means that every potentially faulting operation in parse_command would have to be fenced.

Is there no way process_command can detect that the left side exited with a non-zero exit code?

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  1. Editorial Team
    Editorial Team
    2026-05-23T12:20:18+00:00Added an answer on May 23, 2026 at 12:20 pm

    Does the pipe process continue even if the first process has ended, or is the issue that you have no way of knowing that the first process failed?

    If it’s the latter, you can look at the PIPESTATUS variable (which is actually a BASH array). That will give you the exit code of the first command:

    parse_commands /da/cmd/file | process_commands
    temp=("${PIPESTATUS[@]}")
    if [ ${temp[0]} -ne 0 ]
    then
        echo 'parse_commands failed'
    elif [ ${temp[1]} -ne 0 ]
    then
        echo 'parse_commands worked, but process_commands failed'
    fi
    

    Otherwise, you’ll have to use co-processes.

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