Question

i’ve had a look around, apologies if i’ve duplicated this question

i have a standard list
i.e.

List<String> WordsRequested = new List<String>();

I need to return an XPathNodeIterator of this list

What would be the most efficient way to perform this conversion?

E.G. in pseudo code

XMlDocument xd = new XmlDocument("<WordsRequested></WordsRequested>");
//imaginary method to add each string as a <Word/> Element
xd.Append(WordsRequested, "Word"); 
XPathNodeIterator xpni = xd.Select("//WordsRequest/Word");
return xpni;

I am returning this to an XSLTExtension in Umbraco

Answer 1

Since you are using Umbraco, you can make use of the ‘umbraco.library.Split’ method. This will take a delimited string and return an XPathNodeIterator.

An example XSLT extension would be like this:

public static XPathNodeIterator GetWordsAsXml(List<string> words)
{
    return umbraco.library.Split(string.Join(",", words), ",");
}