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Home/ Questions/Q 7648709
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T10:47:07+00:00 2026-05-31T10:47:07+00:00

I’ve implemented a JQGrid table with loadonce:true like this : jQuery(#list).jqGrid({ datatype: ‘jsonstring’, datastr

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I’ve implemented a JQGrid table with loadonce:true like this :

jQuery("#list").jqGrid({
     datatype: 'jsonstring',
     datastr : maVarJSON,
     colNames:['AA','BB', 'CC','DD','EE','FF'], 
     colModel :[ 
            {name:'invid', index:'invid', align:'center'}, 
            {name:'invdate', index:'invdate'},
            {name:'amount', index:'amount', align:'right'}, 
            {name:'tax', index:'tax', align:'right'}, 
            {name:'total', index:'total', align:'right'}, 
            {name:'note', index:'note'} 
     ],
     pager: jQuery('#pager'),
     rowNum: 50,              
     rowList: [50, 100], 
     caption: '',            
     height: 470,
     width: 1000,       
     loadonce: true          
});
jQuery("#list").jqGrid('filterToolbar',{afterSearch: function(){
            var rowsFiltered = jQuery("#list").getRowData();
 }});

My problem is :
I have 500 rows in maVarJSON. I see 50 rows and 10 pages.
I decide to filter my column AA. Only 100 rows accept this filter. So, I see 50 rows and 2 pages.
I would get the 100 rows data. (The method jQuery("#list").getRowData() give me only the 50 first rows data.)

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T10:47:08+00:00Added an answer on May 31, 2026 at 10:47 am

    The method getRowData get the data from the current page only. If you need get all the grid data you can use getGridParam to get 'data' parameters and get all grid data. I don’t really understand what you want to do with the data inside of afterSearch callback. The goal of filterToolbar to display the data for the user and not to get you JavaScript interface to filter some JavaScript data.

    By the way you can remove caption: '' option which is default, remove loadonce: true which will be ignored for local data inclusive datatype: 'jsonstring' and replace pager: jQuery('#pager') option to pager: '#pager'. If you would use pager: jQuery('#pager') jqGrid will have to convert it to pager: '#pager' itself internally.

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