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Home/ Questions/Q 416979
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T18:32:04+00:00 2026-05-12T18:32:04+00:00

I’ve implemented a repository pattern in my application and in some of my controllers

  • 0

I’ve implemented a repository pattern in my application and in some of my controllers I use a variety of different repositories. (No IoC implemented)

UsersRepository Users;
OtherRepository Other;
Other1Repository Other1;   

public HomeController()
{
     this.Users = new UsersRepository();
     this.Other = new OtherRepository();
     this.Other1 = new Other1Repository();
}

To avoid future issues of bloated controller constructors, I created a wrapper class that contains all the repositories as objects of the class and I call a single instance of this class in my controller constructors.

public class Repositories
{
    UsersRepository Users;
    OtherRepository Other;
    Other1Repository Other1;

    public Repositores()
    {
         this.Users = new UsersRepository();
         this.Other = new OtherRepository();
         this.Other1 = new Other1Repository();
    }
}

In Controller:

Repositories Reps;

public HomeController()
{
     this.Reps= new Repositories();
}

Will this impact the performance of my application now or in the future when the application is expected to grow.

Each repository creates its own DataContext/Entities so for 10 repositories, thats 10 different DataContexts/Entities.

Is DataContext/Entitie an expensive object to create in such a large number?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T18:32:04+00:00Added an answer on May 12, 2026 at 6:32 pm

    You might be better off only creating the repositories when you use them, instead of in the constructor.

    private UsersRepository _usersRepository;
    private  UsersRepository UsersRepository
    {
        get
        {
            if(_usersRepository == null)
            {
                _usersRepository = new UsersRepository();
            }
            return _usersRepository;
        }
    }
    

    Then use the property instead of the field for accessing.

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