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Home/ Questions/Q 8944157
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T11:57:41+00:00 2026-06-15T11:57:41+00:00

I’ve just saved an image (PNG, 200×209) $img = chunk_split(base64_encode(file_get_contents(image.png))); $sql = INSERT INTO

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I’ve just saved an image (PNG, 200×209)

$img = chunk_split(base64_encode(file_get_contents("image.png")));
$sql = "INSERT INTO table (img) VALUES ('$img') WHERE userid = 10";
mysql_query($sql);

(img has a MEDIUMBLOB type)

then trying to obtain it (show.php):

header("Content-type: image/jpeg");

$sql = "SELECT img FROM table WHERE userid = 10 LIMIT 1";
$res = mysql_query($sql);
while ($row = mysql_fetch_assoc($res)) {
    $image = base64_decode($row['img']);
}

echo $image;

when requesting show.php it gives almost the same image, but with another dimension: 136×94 =)

Why that happens?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T11:57:42+00:00Added an answer on June 15, 2026 at 11:57 am

    I recommend you save the image as is. The BLOB datatype of MySQL is specially used for binary data. And this image is a binary file. And remove base64 encodings. It just increases the data size.

    In the code you are saving png image but outputting a jpeg. Both content type should be same.

    So insert code would be something like this,

    $img = file_get_contents("image.png");
    $sql = "INSERT INTO table (img) VALUES ('$img') WHERE userid = 10";
    mysql_query($sql);
    

    And show it as

    header("Content-type: image/png");
    
    $sql = "SELECT img FROM table WHERE userid = 10 LIMIT 1";
    $res = mysql_query($sql);
    echo mysql_result($res, 0);
    
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