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Home/ Questions/Q 3402080
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T05:05:40+00:00 2026-05-18T05:05:40+00:00

I’ve just wrote some code for a basic outline of a page. It for

  • 0

I’ve just wrote some code for a basic outline of a page. It for a game I run, but looking at the code I feel I’ve written it in the wrong order, and that i’m executing more queries than I need to.


    $query = mysql_query("SELECT * FROM bodyguards WHERE username='$u'");

    if($bg = mysql_fetch_assoc($query)) { // if you have a bg
        if($bg[status] == "active") {
            echo "your bodyguard is $bg[bodyguard], kick him?";
        } else {
            echo "invite a bg?";
        }
    } else {
        $query = mysql_query("SELECT * FROM bodyguards WHERE bodyguard='$u' AND status='active'");

        if($bg = mysql_fetch_assoc($query)) { // if you are a bg
            echo "you are the bodyguard of $bg[username]";
        } else {
            //otherwise check if anyone has invited you

            $query = mysql_query("SELECT * FROM bodyguards WHERE bodyguard='$u' AND status='invited'");

            while($temp = mysql_fetch_assoc($query)) {
                echo "$temp[username] has invited you to be their bodyguard, accept or decline?";
            }
        }
    }

i’m only using one database table. if a player1 had a confirmed bodyguard (player2) the row would look like:

username => player1,
bodyguard => player2,
status => active.

would anyone here have written the code in a different way?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T05:05:40+00:00Added an answer on May 18, 2026 at 5:05 am

    I would have done it in a single query:

    $query = mysql_query("SELECT * FROM bodyguards WHERE username='$u' OR (bodyguard='$u' AND (status='active' OR status='invited')");
    
    $bg = mysql_fetch_assoc($query);
    
    if ($bg) { // check for empty result first, to prevent E_NOTICE
        if ($bg['username'] == $u) {
            if($bg['status'] == "active") {
                echo "your bodyguard is {$bg['bodyguard']}, kick him?";
            } else {
                echo "invite a bg?";
            }
        } else if ($bg['bodyguard'] == $u) {
            if ($bg['status'] == "active") {
                echo "you are the bodyguard of {$bg['username']}";
            } else if ($bg['status'] == "invited") {
                echo "{$bg['username']} has invited you to be their bodyguard, accept or decline?";
            }
        }
    }
    

    NOTE: Make sure you are escaping $u if the data is supplied by a user, using mysql_real_escape_string. Also, make sure you quote your array indices to prevent PHP notices (i.e.: use $bg['username'] instead of $bg[username]).

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