Question

I’ve little problem :

I’m solving problem with calling function by pointer and passing to it parameters in continuous memory block.
My goal is to have function named e.g

CallFunc(void * func,void *params, unsigned int param_length);

that I’ll send function pointer, pointer to function’s parameters and eventually parameters length and this calling function will call passed function with it’s parameters.

I will like write this in C/C++, but if somebody has idea, how this resolve in other language, that supports DLL generation and exportet functions, it will be fine too.

Thanks for answers,
Ellesmess

P.S. > I’m sorry about my English, but I’m Czech, thanks :o)

Answer 1

Ok, another try 🙂
Again I’m not sure this is what you need + I believe that you need to change your code style(because from your question I’m filling that you are doing something vary strange).

And here is my solution:

#include <iostream>
#include <boost/function.hpp>
using namespace std;

template <typename Ret>
void CallFunc(boost::function<Ret ()> func)
{
    func();
}


template< typename Ret, typename Arg1>
Ret CallFunc(boost::function<Ret (Arg1)> func, void * args[])
{
    Arg1 * arg1= static_cast<Arg1*> (args[0]);
    return func(*arg1);
}

template<typename Ret, typename Arg1,typename Arg2>
Ret CallFunc(boost::function<Ret (Arg1,Arg2)> func, void * args[])
{
    Arg1 * arg1= static_cast<Arg1*> (args[0]);
    Arg2 * arg2= static_cast<Arg2*> (args[1]);
    return func(*arg1,*arg2);
}

int somefunction(int x)
{
    return x*x;
}


int main()
{
    boost::function<int (int)> func(somefunction);
    int x=17;
    void * args[1];
    args[0]=&x;
    int y = CallFunc(func,args );

    std::cout<<y<<std::endl;
    return 0;
}