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Editorial Team
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Asked: 2026-05-29T08:43:04+00:00

I’ve looked and looked with the debugger and cannot seem to figure out why

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I’ve looked and looked with the debugger and cannot seem to figure out why the IF statement always prints the message.

The IF statement checks to see if yesno != ‘Y’ ||(or) ‘N’
but regardless if i type y or Y or n N or H B it will show… . Im not sure what move to make anymore! I cant seem to find where its going wrong?

if(yesno != 'Y' || 'N') { ...

Thanks guys.

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1 Answer

  1. Editorial Team

    The || doesn’t quite mean what you think it means. The correct approach is:

    if (yesno != 'Y' && yesno != 'N') { ...

    This evaluates each side of the && independently, and the result is true if both sides are true.

    Note that

    if (yesno != 'Y' || yesno != 'N') { ...

    will always be true because any given character is either not Y or it is not N. This is probably not what you want.

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