Question

I’ve looked around for a solution with no luck, here’s what I have and what I’m trying to achieve

Parent Class

public abstract class MyAbstractParentClass{
     private String privateParentField;

     protected String getPrivateParentField(){
          return privateParentField;
     }

     public void setField(String value){
          privateParentField = value;
     }
}

Child Class

public class MyChlidClass extends MyAbstractParentClass{
     @Override
     public void setField(String value){
          super.setField(value);
     }
}

I’m trying to call the MyChlidClass ‘s setField method and then call the MyAbstractParentClass ‘s protected String getPrivateParentField() afterwords;

@Test
public void f(){
    Method[] m = MyChlidClass.class.getDeclaredMethods();
    for (Method method : m) {
        System.out.println(method.getName());
    }
}

But this code above returns only declared methods in MyChlidClass without the parent class’s protected ones, how could I access the protected method? any ideas?

thank you very much in advance 🙂

EDIT
Here’s the final solution for those interested

MyChildClass child = new MyChildClass();
chlid.setField("FOO_BAR");

Method getPrivateParentField = child.getClass().getSuperclass().getDeclaredMethod("getPrivateParentField");
getPrivateParentField.setAccessible(true);

String result = (String) getPrivateParentField.invoke(child);
System.out.println((String)result); //prints out FOO_BAR

PS : there are some exceptions you can either catch or add throws declaration for them;

thanks again for your help

Answer 1

You can get the super class methods by calling

MyChlidClass.class.getSuperclass().getDeclaredMethods();