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Home/ Questions/Q 928367
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T19:59:52+00:00 2026-05-15T19:59:52+00:00

I’ve made a twitter-like web app. Users can follow one another when viewing eachother’s

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I’ve made a twitter-like web app. Users can follow one another when viewing eachother’s pages. Here’s a high-level description of what’s happening:

  • UserA views their own page at http://www.mysite.com/UserA, which renders a list of users they’re following.
  • UserA navigates to UserB’s page at http://www.mysite.com/UserB.
  • UserA follows UserB (via ajax).
  • UserA hits the back button on the browser, to go see their own page again at http://www.mysite.com/UserA.
  • It looks like a cached version of the page is shown, because the list of UserA’s followings is not being shown.
  • If I hit the refresh button, the listing will now be current.

So is there a way to expire the page in the browser, so that it pulls a fresh copy when hitting the back button? Ideally I could do this only if the user had followed another user, otherwise a cached version of the page would be perfect.

I hope the problem is explained clearly enough, please let me know if I can supply more information. I am using a java/servlets based server (google app engine).

Thank you

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  1. Editorial Team
    Editorial Team
    2026-05-15T19:59:53+00:00Added an answer on May 15, 2026 at 7:59 pm

    You need to instruct the webbrowser to not cache the pages in the history so that it’s forced to fire a brand new request to the server when you navigate back in the history. In JSP/Servlet this can be done by adding the following headers to the response of the page(s) you’d like to disable the cache for:

    response.setHeader("Cache-Control", "no-cache, no-store, must-revalidate"); // HTTP 1.1.
    response.setHeader("Pragma", "no-cache"); // HTTP 1.0.
    response.setDateHeader("Expires", 0); // Proxies.
    

    This can be done in a Servlet which forwards to the JSP or a Filter which intercepts on JSP requests.

    See also:

    • Making sure that the page is not cached across browsers
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