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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T06:30:36+00:00 2026-05-15T06:30:36+00:00

I’ve made the example in Java but I think (not tested) that it works

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I’ve made the example in Java but I think (not tested) that it works in other (all?) languages.

You have 2 files. First, M.java:

public class MType {
    XType x;
    MType() {x = null;}
}

Second, another file (in the same directory), XType.java:

public class XType {
   MType m;
   public XType(MType m) {this.m = m;}
}

Ok it’s bad programming, but if you run javac XType it compiles: compiles even MType because XType needs it. But … MType needs XType … how does that work? How does the compiler know what is happening?

I would like to know how the compiler (javac or any other compilers you know) manages that situation, not how to avoid it.

I’m asking because I’m writing a precompiler and I would like to manage that situation.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T06:30:37+00:00Added an answer on May 15, 2026 at 6:30 am

    You need to take a 2-pass, or multi-pass approach:

    Languages like Java require a multi-pass compiler since the definition of x would not be required to come before the use:

    public class Example {  
    public static void main(String [] args) {
        assert(x==0);           
        x++;
        assert(x==1);
    }
    static int x=0;
    }
    

    There are various approaches, for example you could do the following:

    The first pass could look for all variable declarations, the second for method declarations, etc. until the last pass uses all this information to compile the final code.

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