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Home/ Questions/Q 858035
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T08:29:22+00:00 2026-05-15T08:29:22+00:00

I’ve notice this. Example: create an empty text file called for example ast.py $

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I’ve notice this. Example:

create an empty text file called for example ast.py

$ touch ast.py

run Python

$ python
>>> from ast import *
>>> dir()
['__builtins__', '__doc__', '__name__', '__package__']
>>> from _ast import *
>>> dir()
['AST', 'Add', 'And', 'Assert', 'Assign', ...]

ast is a python module. So… what’s happening here? I tried with an empty os.py and didn’t work.

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  1. Editorial Team
    Editorial Team
    2026-05-15T08:29:23+00:00Added an answer on May 15, 2026 at 8:29 am

    There’s nothing special with _xxx modules except they are private (e.g. _abcoll) or low-level (e.g. _thread) and not intended to be used in general.

    The _ast module is special, e.g.

    $ touch _ast.py
    $ python -c 'from _ast import *; print(dir())'
    ['AST', 'Add', 'And', 'Assert', 'Assign', 'Attribute ...
    

    But this is not because of the leading _, but that _ast is a built-in module. Similar thing happens with the sys module.

    $ touch sys.py
    $ python -c 'from sys import *; print(dir())'
    ['__builtins__', '__doc__', '__name__', '__package__', 'api_version', 'argv', ...
    

    In Python _ast and ast are two separate modules. There is a line

    from _ast import *
    

    in the built-in ast.py, so importing ast will also bring everything from the _ast module in. This gives you the illusion that _ast and ast have the same content, but actually _ast is a lower level module of ast.

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