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Asked: 2026-05-11T11:03:14+00:00

I’ve noticed that whenever I write a program that uses std::cin that if I

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I’ve noticed that whenever I write a program that uses std::cin that if I want the user to press Enter to end the program, I have to write std::cin.ignore() twice to obtain the desired behavior. For example:

#include <iostream>  int main(void) {     int val = 0;     std::cout << 'Enter an integer: ';     std::cin >> val;      std::cout << 'Please press Enter to continue...' << std::endl;      std::cin.ignore();     std::cin.ignore();  // Why is this one needed? }

I’ve also noticed that when I’m not using cin for actual input but rather just for the ignore() call at the end, I only need one.

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1 Answer

  1. Discl: I’m simplifying what really happens.

    The first serves to purge what the extraction operator (>>) hasn’t consumed. The second waits for another \n.

    It is exactly the same when we do a std::getline after an extraction: a the_stream::ignore(std::numeric_limits<streamsize>::max(), '\n'); is required before the call to std::getline()

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