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Home/ Questions/Q 4544582
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T15:41:30+00:00 2026-05-21T15:41:30+00:00

I’ve placed a set of .rb files in a directory modules/ . Each of

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I’ve placed a set of .rb files in a directory modules/. Each of these files contains a module. I’m loading all of these files from a separate script with this:

Dir["modules/*.rb"].each {|file| load file }

But then I have to include them, one by one, listing and naming each of them explicitly:

class Foo
  include ModuleA
  include ModuleB
  # ... and so on.
end

I’m wondering if there is some non-explicit one-liner that can accomplish this, a la (pseudocode) …

class Foo
  for each loaded file
    include the module(s) within that file
  end
  # ... other stuff.
end

I’ve considered actually reading the files’ contents, searching for the string “module“, and then extracting the module name, and somehow doing the include based on that — but that seems ridiculous.

Is what I’m trying to do advisable and/or possible?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T15:41:31+00:00Added an answer on May 21, 2026 at 3:41 pm

    You can manually define some variable in each of your file and then check for its value while including the file.

    For example, module1.rb:

    export = ["MyModule"]
    
    module MyModule
    
    end
    

    And the second one, module2.rb:

    export = ["AnotherModule", "ThirdModule"]
    
    module AnotherModule
    
    end
    
    module ThirdModule
    
    end
    

    And then just include all of them in your file (just the idea, it may not work correctly):

    class Foo
        Dir["modules/*.rb"].each do |file| 
            load file
            if export != nil
                 export.each do { |m| include(Kernel.const_get(m))
            end 
        end
    end
    
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