Question

I’ve ran into an error where I keep getting “is not a type name” for the ‘use’ function in the cpp file. I’m trying to make an array of structs, to store data for “Items”. I’m making a text based RPG game, so I’m trying to create an item class, that has a use function, to use the various items (In the struct array) on the characters. I’ve tried writing this several different ways and calling it other ways, but I can’t get this error to go away. Even placing the struct before the class, in the public, etc.

class Items 
{ 
private:
    struct eating
    {
        int itemNumber;
        char name[30];
    };

public:
    Items();
    eating useables[10];
    void use(useables);
};


void Items::use(useables) // Error is here, tells me useables is not a type name
{
    // To use items on characters
}

Answer 1

You need to pass a type and a name to your function:

void Items::use(eating useables)
{
    // To use items on characters
}

In the case you just wanted to use the internal useables object, you don’t need to pass it to the function and can just write

void Items::use()
{
    useables[1].itemNumber = 1; // For instance
}