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Home/ Questions/Q 5930587
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T14:34:30+00:00 2026-05-22T14:34:30+00:00

I’ve ran into an interesting problem. I have the following code: cout << \nFILE;

  • 0

I’ve ran into an interesting problem. I have the following code:

cout << "\nFILE";
cout << "\tLocation:" << file.location << endl;
cout << "\tLocation (c_str()): " << file.location.c_str() << endl;

where location is set by a function that finds a file location in a file with the format

DRIVE:\dir1\dir2…\filename.extension

For example, the function will have successfully set file.location to

C:\Documents and Settings\admin\testfile.foo

However, the strangest thing happens. It outputs something that looks like this:

FILE

Location: C:\Documents and Settings\admin\testfile.foo

Location (c_str()): C:\Documents

Note the lack of the remaining file path. Being the astute programmer I am, I decided to test absolute paths. I physically set the string file.location to

C:\\Documents and Settings\\admin\\testfile.foo

and the corresponding output was

FILE

Location: C:\Documents and Settings\admin\testfile.foo

Location (c_str()): C:\Documents and Settings\admin\testfile.foo

as expected. I then tested

C:\Documents and Settings\admin\testfile.foo

and the output was

FILE

Location: C:Documents and Settingsadmintestfile.foo

Location (c_str()): C:Documents and Settingsadmintestfile.foo

also expected.

I cannot for the life of me figure out what could possibly be going wrong. The file path is clearly correct in the string itself, why would it change only in this case?

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  1. Editorial Team
    Editorial Team
    2026-05-22T14:34:31+00:00Added an answer on May 22, 2026 at 2:34 pm

    There are so many wrong things in your code… Here is the number 1 problem:

    temp2 = char(HexToInt(temp2));
    

    temp2 is empty at this point, so HexToInt returns 0.

    Here are more problem:

    temp = Location[i+1] + Location[i+2]; 
    

    this adds two char resulting in an int. It does not concatenate them. Use std::string::substr instead.

    temp += j * pow(16.00, k);
    

    don’t use floating point like this.

    P.S. and this just demonstrates that you code is more important than your problem description.

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