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Home/ Questions/Q 963469
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T01:40:31+00:00 2026-05-16T01:40:31+00:00

I’ve read a few solutions on here, but my problem differs enough where those

  • 0

I’ve read a few solutions on here, but my problem differs enough where those will not work. Basically if the radio button is checked, add a css class to the parent div. If the radio is not checked, remove the css class. Sounds simple?

I have more than one radio button group, so in other words, there will be multiple radio buttons selected at a time. Each radio button group also is on different parts of the page seperated by other html.

Here is what I came up with:

  $(document).ready(function () {
    $('input').click(function () {
        if ($('input:not(:checked)')) {
            $('div').removeClass('style1');
        }
        if ($('input').is(':checked')) {
            $(this).parent().addClass('style1');
        }


    });
});

I think I’m on the right path with the input:not(:checked), but on the next line it removes style1 from all div elements instead of checking if other divs radio button child is checked.

I guess what I’m asking is how do I write a script that when a radio button is clicked, add a css class to the parent and then find all div tags on the page that have a child of input. If the divs child input is not checked, remove the css class. So if a div has a child input element and it is checked, don’t remove the css class from the inputs div.

I hope that makes sense.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T01:40:32+00:00Added an answer on May 16, 2026 at 1:40 am

    Why not using the following: http://jsfiddle.net/Q2bzT/

    $(document).ready(function () {
        $('input').click(function () {
            $('input:not(:checked)').parent().removeClass("style1");
            $('input:checked').parent().addClass("style1");
        });    
    });​
    
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