I’ve read a LOT of things about this problem, however I still cannot fix it.
In my functions file I declare a variable with a value like so:
$px_host = "localhost";
And I have a database query function like so:
function dbQuery($database, $reqquery){
if(!$connect = mysql_connect($px_host, $px_dbuser, $px_dbpass)){
exit("Error - cannot connect to MySQL server - " . mysql_error());
}
if(!$database = mysql_select_db($database)){
exit("Error - cannot select database - " . mysql_error());
}
if(!$query = mysql_query($reqquery)){
exit("Error - query error.");
}
return $query;
}
And whenever I try and run the function, I get an ‘Undefined Variable’ error. I’ve tried setting the variable to global, however it still says it’s undefined. They are in the same file and the variable is defined and set before the function.
(I’m bad at explaining this so try and work round it)
The file which contains dbQuery() is included in another file. In the other file, there is a function which uses dbQuery() to get certain information. Is it possible that because it’s being initially run from the first file, the variable is outside the scope?
In your specific case you should declare global within function all variables outside the function. So
But your code can be improved: You should define constants at the beginning of your script
and use constants inside the function (so no need to declare global, and it’s more logic because host, user and pass aren’t variable but constants).
You should connect at database only once at the beginning of your flow so the function
dbQueryexecute only the query (according with the function name).EDIT for completeness of answer:
As some users say you in other comments, I invite you to read the php doc for mysql_connect and see the red advise:
I’m not here for say you what you MUST do in your project, but read the doc and follow the tipps/suggestions is essential for the success of your project. 🙂