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Home/ Questions/Q 4607230
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T00:40:26+00:00 2026-05-22T00:40:26+00:00

I’ve read a thread on what a (non)subscriptable object is but it doesn’t tell

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I’ve read a thread on what a (non)subscriptable object is but it doesn’t tell me what i can do about it.

I have a code calling a mypost private module. The aim is to set up mail accounts and to do this i create MailAccounts() objects defined in the mypost module. Quantity of accounts and their respective details are described in a configuration file. When the application starts, it collects account information and stores it in a dictionary, the structure of which is: accounts = {service : { <MailAccounts Object at xxxxx> : {username : myusername, password : mypassword}}} where service can be “gmail” and where MailAccounts is the class defined in the mypost module.
So far so good. When however i want to setup the account, i need to call its method: MailAccounts.setupAccount(username, password). I do this by iterating each MailAccount object of the dictionary and ask to run the method:

for service in accounts:
        for account in accounts[service]:
            account.setupAccount(account['username'], account['password'])

But as you may have guessed it didn’t work, Python returns:

TypeError: 'MailAccount' object is not subscriptable

If i create the same account manually however it works:

account = MailAccount()
account.setupAccount('myusername', 'mypassword')

Now i believe it has something to do with the fact that my <MailAccount Object at xxxx> is a dictionary key right? That makes it non-subscriptable (whatever that may mean)?

No what exactly does this mean to be non-subscriptable? What does it imply in this example? And of course: how can i solve / bypass this in this case?

Thanks,
Benjamin 🙂

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  1. Editorial Team
    Editorial Team
    2026-05-22T00:40:27+00:00Added an answer on May 22, 2026 at 12:40 am

    The way to fix it is to use dictionaries properly.

    for service in accounts:
            for account, creds in accounts[service].iteritems():
                account.setupAccount(creds['username'], creds['password'])
    
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