Question

I’ve read in manual:

For bit-oriented delivery, the bit
order for the byte stream format is
specified to start with the MSB of the
first byte, proceed to the LSB of the
first byte, followed by the MSB of the
second byte, etc.

In my application I have to cope with bits.
(for example I have decimal number 5, in binary format it looks like 00000101)
So, is that means (according to manual) that order of bits I read is

<= 0 <= 0 <= 0 <= 0 <= 0 <= 1 <= 0 <= 1 (first read bit I read is 0, second is 0 etc....)

or it means such order of reading bits:

<= 1 <= 0 <= 1 <= 0 <= 0 <= 0 <= 0 <= 0 (first read bit I read is 1, second is 0 etc....)

Thanks

Answer 1

• MSB: Most significant bit
• LSB: Least significant bit

So for 5 (0000_0101) the bit on the left (representing 2⁷) is “most significant” and the bit on the right (representing 2⁰) is the “least significant”. Therefore, yes, expect 0 to be the first bit.