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Home/ Questions/Q 6816659
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T20:57:08+00:00 2026-05-26T20:57:08+00:00

I’ve read several articles on closures and what not but im attempting to create

  • 0

I’ve read several articles on closures and what not but im attempting to create a specific named function

from app.conf import html_helpers

# html_helpers = ['img','js','meta']

def _makefunc(val):
    def result(): # Make this name of function?
        return val()
    return result

def _load_func_from_module(module_list):
    for module in module_list:
        m = __import__("app.system.contrib.html.%s" % (module,), fromlist="*")
        for attr in [a for a in dir(m) if '_' not in a]:
            if attr in html_helpers and hasattr(m, attr):
                idx = html_helpers.index(attr)
                html_helpers[idx] = _makefunc(getattr(m,attr))

def _load_helpers():
    """ defines what helper methods to expose to all templates """
    m = __import__("app.system.contrib.html", fromlist=['elements','textfilter'])
    modules = list()
    for attr in [a for a in dir(m) if '_' not in a]:
        print attr
        modules.append(attr)
    return _load_func_from_module(modules)

img return a modified string like so when i call _load_helpers i want to modify the existing list of strings to those functions im calling.

is this possible and am i making any sense because i am confused 🙁

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T20:57:08+00:00Added an answer on May 26, 2026 at 8:57 pm

    I think functools.wraps should do what you want:

    from functools import wraps
    
    def _makefunc(val):
        @wraps(val)
        def result():
            return val()
        return result
    
    >>> somefunc = _makefunc(list)
    >>> somefunc()
    []
    >>> somefunc.__name__
    'list'
    
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