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Home/ Questions/Q 3353722
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T02:11:08+00:00 2026-05-18T02:11:08+00:00

I’ve read that C89 does not support variable-length arrays, but the following experiment seems

  • 0

I’ve read that C89 does not support variable-length arrays, but the following experiment seems to disprove that:

#include <stdio.h>

int main()
{
   int x;
   printf("Enter a number: ");
   scanf("%d", &x);
   int a[x];
   a[0] = 1;
   // ...
   return 0;
}

When I compile as such (assuming filename is va_test.c):

gcc va_test.c -std=c89 -o va_test

It works…

What am I missing? 🙂

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  1. Editorial Team
    Editorial Team
    2026-05-18T02:11:09+00:00Added an answer on May 18, 2026 at 2:11 am

    GCC always supported variable length arrays AFAIK. Setting -std to C89 doesn’t turn off GCC extensions …

    Edit: In fact if you check here:

    http://gcc.gnu.org/onlinedocs/gcc/C-Dialect-Options.html#C-Dialect-Options

    Under -std= you will find the following:

    ISO C90 programs (certain GNU
    extensions that conflict with ISO C90
    are disabled). Same as -ansi for C
    code.

    Pay close attention to the word “certain”.

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