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Home/ Questions/Q 7825893
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T09:11:43+00:00 2026-06-02T09:11:43+00:00

I’ve run into a small issue here. I have an unsigned char array, and

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I’ve run into a small issue here. I have an unsigned char array, and I am trying to access bytes 2-3 (0xFF and 0xFF) and get their value as a short.

Code:

 unsigned char Temp[512] = {0x00,0xFF,0xFF,0x00};
 short val = (short)*((unsigned char*)Temp+1)

While I would expect val to contain 0xFFFF it actually contains 0x00FF. What am I doing wrong?

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  1. Editorial Team
    Editorial Team
    2026-06-02T09:11:44+00:00Added an answer on June 2, 2026 at 9:11 am

    There’s no guarantee that you can access a short when the data is improperly aligned.

    On some machines, especially RISC machines, you’d get a bus error and core dump for misaligned access. On other machines, the misaligned access would involve a trap into the kernel to fix up the error — which is only a little quicker than the core dump.

    To get the result reliably, you’d be best off doing shifting and or:

    val = *(Temp+1) << 8 | *(Temp+2);
    

    or:

    val = *(Temp+2) << 8 | *(Temp+1);
    

    Note that this explicitly offers big-endian (first option) or little-endian (second) interpretation of the data.

    Also note the careful use of << and |; if you use + instead of |, you have to parenthesize the shift expression or use multiplication instead of shift:

    val = (*(Temp+1) << 8) + *(Temp+2);
    val = *(Temp+1) * 256 + *(Temp+2);
    

    Be logical and use either logic or arithmetic and not a mixture.

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