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Home/ Questions/Q 7051881
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T03:19:00+00:00 2026-05-28T03:19:00+00:00

I’ve run into the same problem in two different pieces of work this month:

  • 0

I’ve run into the same problem in two different pieces of work this month:

Version 1: User 1 & User 2 are friends
Version 2: Axis 1 & Axis 2 when graphed should have the quadrants colored...

The problem is, I don’t see an elegant way, using a RDBMS, to store and query this information.

There are two obvious approaches:

Approach 1:

store the information twice (i.e. two db rows rows per relationship):
u1, u2, true 
u2, u1, true
u..n, u..i, true
u..i, u..n, true

have rules to always look for the inverse on updates: 
on read, no management needed
on create, create inverse
on delete, delete inverse
on update, update inverse

Advantage:    management logic is always the same.
Disadvantage: possibility of race conditions, extra storage (which is admittedly cheap, but feels wrong)

Approach 2:

store the information once (i.e. one db row per relationship)
u1, u2, true
u..n, u..i, true

have rules to check for corollaries:
on read, if u1, u2 fails, check for u2, u1 
on create u1, u2: check for u2, u1, if it doesn't exist, create u1, u2
on delete, no management needed
on update, optionally redo same check as create

Advantage: Only store once
Disadvantage: Management requires different set of cleanup depending on the operation

I’m wondering if there’s a 3rd approach that goes along the lines of “key using f(x,y) where f(x,y) is unique for every x,y combination and where f(x,y) === f(y,x)”

My gut tells me that there should be some combination of bitwise operations that can fulfill these requirements. Something like a two-column:

key1 = x && y
key2 = x + y

I’m hoping that people who spent more time in the math department, and less time in the sociology department have seen a proof of the possibility or impossibility of this and can provide a quick “[You moron,] its easily proven (im)possible, see this link” (name calling optional)

Any other elegant approach would also be very welcome.

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T03:19:00+00:00Added an answer on May 28, 2026 at 3:19 am

    There is also a way to use the 2nd approach by adding an extra constraint. Check that u1 < u2:

    CREATE TABLE User
    ( Name VARCHAR(10) NOT NULL
    , PRIMARY KEY (Name)
    ) ;
    
    CREATE TABLE MutualFriendship
    ( u1 VARCHAR(10) NOT NULL
    , u2 VARCHAR(10) NOT NULL
    , PRIMARY KEY (u1, u2)
    , FOREIGN KEY (u1) 
        REFERENCES User(Name)
    , FOREIGN KEY (u2) 
        REFERENCES User(Name)
    , CHECK (u1 < u2) 
    ) ;
    

    The rules to read, create, insert or update will have to use the (LEAST(u1,u2), GREATEST(u1,u2)).

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