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Home/ Questions/Q 7962033
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T05:13:07+00:00 2026-06-04T05:13:07+00:00

I’ve searched here and the web for a solution, but they just seem to

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I’ve searched here and the web for a solution, but they just seem to cause other errors I’m too inexperienced with (the first build was in PHP, now I have to move it to a stored procedure). What I have is a map of my campus, and when a user clicks on a building, an info bubble pops open to show some information and a gallery of pictures. The address of the picture are stored in a table, so I need them to come back in an array so I can loop through them. The call to get the list is:

$.ajax({ //get the picture URLs, load into array
        type: "post",
        url: "video_tour.get_pics",
        data: { pBldg_id:  building
        },
        error: function(xhr,thrownError) { alert("error get pics"); },
        success: function(data){
                  $.each(data, function(index,obj) {
                         picArray[index] = obj.ADDRESS;
                  });
        }
});//and ajax for pic load

and the called procedure:

procedure get_pics(pBldg_id int) is
     type array_varchar is table of varchar2(2000) index by binary_integer;

     array_of_pics array_varchar;
     v_counter int := 0;
begin

for i in(select address from ucs.campus_pictures where building_id = pBldg_id and thumbnail = 1) loop
     array_of_pics(v_counter) := i.address;
     v_counter := v_counter + 1;
end loop;               

end get_pics;

How can I can I take the array_of_pics back to the ajax call?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T05:13:09+00:00Added an answer on June 4, 2026 at 5:13 am

    So it wasn’t as complex as it seemed, I just need to print the data as it comes out and add a delimiting character:

      for i in(select address from ucs.campus_pictures where building_id = pBldg_id and thumbnail = 1) loop
    htp.prn(i.address || ';');
    end loop; 
    

    and make an array in the ajax call:

     $.ajax({ //get the picture URLs, load into array
                         type: "post",
                         url: "video_tour.get_pics",
                         data: { pBldg_id:  building
                         },
                         error: function(xhr,thrownError) { alert("error get pics"); }, 
                         success: function(data){
                          $.each(data.split(";"), function(index,obj) {
                                        picArray[index] = obj;
                                  });
    
                         }
                });
    

    Thanks guys for taking the time to help!

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