Question

I’ve searched through google (maybe I didn’t look hard enough) but I could not find how to turn Math.sqrt into an int.

I want to use Math.sqrt for a for loop and I guess I need it as an int but I can’t seem to figure out how to cast the result to an int. So how do I do it?

I tried something similar to Java:

(int) Math.sqrt(num); 

But it didn’t work.

Thanks in advance 🙂

Answer 1

Use Math.round, Math.ceil, or Math.floor depending on your specific rounding needs.

‘For rounding numbers to integers one of Math.round, Math.ceil and Math.floor are preferable, and for a desired result that can be expressed as a 32 bit signed integer the bitwise operation described below might also suit.’

–http://www.jibbering.com/faq/faq_notes/type_convert.html#tcNumber