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Home/ Questions/Q 6241393
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T11:45:38+00:00 2026-05-24T11:45:38+00:00

I’ve seen a couple of methods on how to do this. My own method

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I’ve seen a couple of methods on how to do this. My own method that I like, except from one part, is the following:

  1. Hijack submit-event of form
  2. Collect the data and build a json object

    var objToSend = { Property : $('#propertyField').val(), Property2 : ... };
    

    This is the part I don’t like since it’s tedious to collect 25 values like this

  3. Call $.ajax({}) and specify the url to point to an [HttpPost] enabled action somewhere

  4. in the success: part of the ajax-query, collect the returned data (which I return as a string) and write it out where appropriate. I handle errors here as well, checking to see if the first word is “Error:” and then taking appropriate action.

I like this method apart from the collection stage. I am sure there is a better way of doing this but I’v thrown myself headlong into jquery coming from an ASP.NET WebForms-background so the whole “embrace the web” part is totally foreign to me.

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  1. Editorial Team
    Editorial Team
    2026-05-24T11:45:39+00:00Added an answer on May 24, 2026 at 11:45 am

    You could use the serialize() method to avoid passing all the fields one by one. It will send the entire form data to the server using application/x-www-form-urlencoded content type as if it was a standard form submission:

    $('#myform').submit(function() {
        $.ajax({
            url: this.action,
            type: this.method,
            data: $(this).serialize(),
            success: function(result) {
                // TODO: handle the success case
            }     
        });
        return false;
    });
    

    Another possibility is the jQuery form plugin:

    $('#myform').ajaxForm(function(result) { 
        // TODO: handle the success case
    });
    

    Some people find it also useful to use the Ajax.BeginForm helpers to render the form:

    @using (Ajax.BeginForm(new AjaxOptions { OnSuccess = "success" }))
    {
        ... some input fields
    }
    

    In ASP.NET MVC 3 you need to include the jquery.unobtrusive-ajax.js script which unobtrusively AJAXifies the HTML 5 data-* attributes emitted by the Ajax helper.

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