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Home/ Questions/Q 8124233
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T06:24:11+00:00 2026-06-06T06:24:11+00:00

I’ve seen plenty of examples on how to write to excel, and my program

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I’ve seen plenty of examples on how to write to excel, and my program requires reading from existing data. I need to read through a column and pick out numbers from it (the column is empty cells with numbers at arbitrary intervals), and then break out when I reach the end of the data. The code I have now is below, where xlsht is the sheet name, x and y are the cell indices, and address is the list all the numbers are going.

while y < xlsht.UsedRange:
    if str(xlsht.Cells(x,y).Value).isdigit:
        address.append(xlsht.Cells(x,y).Value)
        y += 1
        continue
    else:
        y += 1
return address

As it stands now, it crashes at line 2. I tried using

if xlsht.Cells(x,y).Value not None:

but that didn’t work. I dont know how else to do this. Also, I wanted to verify that using

xlsht.UsedRange 

is the correct way of detecting the last row of the sheet.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T06:24:13+00:00Added an answer on June 6, 2026 at 6:24 am

    The error message doesn’t give any useful clues what the problem might be.

    Soltuion: Poor man’s debugger. Print all and any variables so you can see what is going on:

    print 'xlsht=',xlsht
    print 'x=',x
    print 'usedRange=',xlsht.UsedRange
    while y < xlsht.UsedRange:
        print 'y=',y
        print 'cell=',xlsht.Cells(x,y)
        print 'value=',xlsht.Cells(x,y).Value
        if str(xlsht.Cells(x,y).Value).isdigit:
            address.append(xlsht.Cells(x,y).Value)
            y += 1
            continue
        else:
            y += 1
    return address
    

    You get the idea. If you’re using Python 3.x, you’ll need print('x=',repr(x))

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