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Home/ Questions/Q 7585801
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T19:15:44+00:00 2026-05-30T19:15:44+00:00

I’ve seen references to cut-and-paste proofs in certain texts on algorithms analysis and design.

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I’ve seen references to cut-and-paste proofs in certain texts on algorithms analysis and design. It is often mentioned within the context of Dynamic Programming when proving optimal substructure for an optimization problem (See Chapter 15.3 CLRS). It also shows up on graphs manipulation.

What is the main idea of such proofs? How do I go about using them to prove the correctness of an algorithm or the convenience of a particular approach?

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  1. Editorial Team
    Editorial Team
    2026-05-30T19:15:45+00:00Added an answer on May 30, 2026 at 7:15 pm

    The term “cut and paste” shows up in algorithms sometimes when doing dynamic programming (and other things too, but that is where I first saw it). The idea is that in order to use dynamic programming, the problem you are trying to solve probably has some kind of underlying redundancy. You use a table or similar technique to avoid solving the same optimization problems over and over again. Of course, before you start trying to use dynamic programming, it would be nice to prove that the problem has this redundancy in it, otherwise you won’t gain anything by using a table. This is often called the “optimal subproblem” property (e.g., in CLRS).

    The “cut and paste” technique is a way to prove that a problem has this property. In particular, you want to show that when you come up with an optimal solution to a problem, you have necessarily used optimal solutions to the constituent subproblems. The proof is by contradiction. Suppose you came up with an optimal solution to a problem by using suboptimal solutions to subproblems. Then, if you were to replace (“cut”) those suboptimal subproblem solutions with optimal subproblem solutions (by “pasting” them in), you would improve your optimal solution. But, since your solution was optimal by assumption, you have a contradiction. There are some other steps involved in such a proof, but that is the “cut and paste” part.

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