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Home/ Questions/Q 7051025
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T03:12:53+00:00 2026-05-28T03:12:53+00:00

I’ve spent a bit searching The Google as well as SO and have been

  • 0

I’ve spent a bit searching The Google as well as SO and have been unable to find an answer for this simple question:

What sort of issue would generate an E_COMPILE_WARNING in PHP?

The PHP manual entry on the subject docs says of E_COMPILE_WARNING:

Compile-time warnings (non-fatal errors). This is like an E_WARNING,
except it is generated by the Zend Scripting Engine.

But I’m not sure what this would constitute. What’s the difference between a regular E_WARNING and a warning raised by the Zend Scripting Engine? Could someone please explain and provide a code snippet if applicable?

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  1. Editorial Team
    Editorial Team
    2026-05-28T03:12:53+00:00Added an answer on May 28, 2026 at 3:12 am

    Basically, the difference between an E_WARNING and an E_COMPILE_WARNING is that E_COMPILE_WARNING is generated while the script is still compiling.

    E_COMPILE_WARNING is similar to E_COMPILE_ERROR in that it is generated during compile time, but an E_COMPILE_WARNING does not prevent script execution the way E_COMPILE_ERROR does. Compare it to the the relation between E_ERROR and E_WARNING, where the former halts execution, and the latter allows execution to continue.

    For example, the following code generates an E_COMPILE_WARNING:

    <?php
        echo "\n";
        echo "Hello World";
        echo "\n\n";
        var_dump(error_get_last());
        declare(foo='bar');
    ?>
    

    output:

    Warning: Unsupported declare 'foo' in e_compile_warning.php on line 6
    
    Hello World
    
    array(4) {
      ["type"]=>
      int(128)
      ["message"]=>
      string(25) "Unsupported declare 'foo'"
      ["file"]=>
      string(124) "e_compile_warning.php"
      ["line"]=>
      int(6)
    }
    

    Notice how the warning is displayed before the other output (even though “Hello World” came first in the source), and the var_dump statement on line 5 references an error that occurs on line 6. PHP compiles the script, doesn’t like declare(foo='bar');, but goes back and executes the script anyway (as opposed to an E_COMPILE_ERROR like $this = 2;, which would stop execution (and compilation) immediately).

    Hope this helps!

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