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Home/ Questions/Q 5985141
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T22:29:08+00:00 2026-05-22T22:29:08+00:00

I’ve started learning C in my course and I’m having some trouble debugging a

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I’ve started learning C in my course and I’m having some trouble debugging a program I’m making. The program is an emulator for a simplified MIPS language and basically I’m trying to read in a binary file of 32-bit instructions and store it directly into an array so that my program can go through the instructions with a program counter.

Anyway, in my first attempt at the program I had the memory that the file was read into as a 32-bit int array. The emulator worked fine and the results of my emulator matched the expected results.

The specification wanted the emulator to be byte addressable however, so I changed the memory to an array of 1-byte chars. I then changed the rest of the program as appropriate so that it would make sure it read each instruction by taking 4 blocks of chars.

In the int version of my emulator:

int loadBin(char path[]) {

printf("%s\n",path);

//open file
FILE *fp;
if ((fp = fopen(path, "rb")) == NULL) {
    perror("Error opening binary file");
    return 1;
}
//read from file to memory
fread(&vm.memory, 4, 16384, fp);

}

ANd in the char version:

int loadBin(char path[]) {
//open file
FILE *fp;
if ((fp = fopen(path, "rb")) == NULL) {
perror("Error opening binary file");
return 1;
}
//read from file to memory
fread(&vm.memory, 1, 65536, fp);
fclose(fp);

return 0;
}

But the char memory emulator read an incorrect 32-bit instruction half way through the program.

Using:

int test = (vm.memory[16]) + (vm.memory[17] << 8) +
(vm.memory[18] << 16) + (vm.memory[19] << 24);
printf("%d\n", test);
return 0;

results in a DIFFERENT number from what I get in the int array at vm.memory[4] which should be exactly the same. The results up to vm.memory[4] are the same in the char array, but for some reason something goes wrong. Can anybody help?

Thx

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T22:29:09+00:00Added an answer on May 22, 2026 at 10:29 pm

    Your char array should be aligned at a 32-bit boundary if you’re going to be reading/writing 32-bit words from it. If you used malloc to allocate this array, then it’s already aligned.

    Instead of this:

    int test = (vm.memory[16]) + (vm.memory[17] << 8) +
    (vm.memory[18] << 16) + (vm.memory[19] << 24);
    

    try this:

    int test = (vm.memory[16]) | (vm.memory[17] << 8) |
    (vm.memory[18] << 16) | (vm.memory[19] << 24);
    

    | is the bitwise OR operator. + uses 2’s-complement arithmetic, so you might get weird results when integers are negative, or when there’s overflow.

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