Question

I’ve started making a Video script that loads the videos using MySql and I am using Mysqli.
However, There’s 2 Rows that it should post, but it only post the second none, not the first one.
It loads the results using “Brand” so if there’s 2 rows named “Test”, it only loads the second one, but not the first one.
So, what is causing this? I’ve tried with 3 rows, and it did not include the first row.
Code

<?php
{ /* Global Data */
ini_set('display_errors', 0); 
ini_set('error_reporting', -0);
$GetPath = $_GET['b'];
$SqlUser = "root";
$SqlPass = "**Private**";
$SqlHost = "localhost";
$SqlData = "heisteknikk";
}
{ /* Mysql Connect */
$Sql = new mysqli($SqlHost, $SqlUser, $SqlPass, $SqlData);
if ($Sql->connect_error) { die("Sorry, Could not connect (".$Sql->connect_errno.") ".$Sql->connect_error);}
}
{ /* Test */

$Brand = $Sql->real_escape_string($GetPath);
$SqlData = "SELECT * FROM videos WHERE Brand = '".$Brand."'";
$SqlQuery = $Sql->query($SqlData);
if (!$SqlQuery) {
    echo $Sql->error;
}
if ($SqlQuery->num_rows == 0) {
die("Nothing was found");
}
$Data = $SqlQuery->fetch_array(MYSQLI_ASSOC);
echo "<table border='1'>";
while ($Heis = $SqlQuery->fetch_assoc()) {
echo "
<tr><td>".$Heis['Brand']."</td><td>".$Heis['Name']."</td><td>".$Heis['Location']."


";
}
echo "</table>";
$Sql->close();
}
?>

Answer 1

This line causes the bug:

$Data = $SqlQuery->fetch_array(MYSQLI_ASSOC);

With this line you effectively throw out the first row of the result set, as you don’t process $Data at all in the code below. Just remove it, and your script should work fine (I assume that closing </td></tr> sequence was lost when pasting the code, am I right?)