Question

I’ve stored a very large number in a float variable, but when I print it I want to only display the whole number part and nothing after the decimal point.

For numbers in the int or long range, I would do a casting but this hasn’t helped me because the number I want to print is too long for int or long.

I’ve looked at this explanation: http://www.cprogramming.com/tutorial/printf-format-strings.html but I haven’t succeeded in solving this.

this is my code and my attempt to do the casting:

double sum=552074001368;
long long_sum;
long_sum = (long)(sum);      //int casting for double "add" 
if(sum>=0) printf("=\n%ld\n",long_sum);
else printf("=\n%ld\n",-long_sum);

I don’t want to use a specific precision like printf("%15f") because this variable fluctuates and is sometimes very short like 4 digits.

Answer 1

I think what you’re after is %.0f. For example:

#include <stdio.h>

int main(){

    double x = 1234.567;

    printf("%.0f", x);
    return 0;
}

…prints:

1235