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Home/ Questions/Q 7569657
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T15:13:16+00:00 2026-05-30T15:13:16+00:00

I’ve the following two columns in Postgres table name | last_name —————- AA |

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I’ve the following two columns in Postgres table

name | last_name
----------------
AA   | AA aa
BBB  | BBB bbbb
.... | ..... 
.... | ..... 

How can I update the last_name by removing name text from it?

final out put should be like

name | last_name
----------------
AA   | aa
BBB  | bbbb
.... | ..... 
.... | ..... 
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  1. Editorial Team
    Editorial Team
    2026-05-30T15:13:17+00:00Added an answer on May 30, 2026 at 3:13 pm
    UPDATE table SET last_name = regexp_replace(last_name, '^' || name || ' ', '');
    

    This only removes one copy from the beginning of the column and correctly removes the trailing space.

    Edit

    I’m using a regular expression here. '^' || name || ' ' builds the regular expression, so with the ‘Davis McDavis’ example, it builds the regular expression '^Davis '. The ^ causes the regular expression to be anchored to the beginning of the string, so it’s going to match the word ‘Davis’ followed by a space only at the beginning of the string it is replacing in, which is the last_name column.

    You could achieve the same effect without regular expressions like this:

    UPDATE table SET last_name = substr(last_name, length(name) + 2);
    

    You need to add two to the length to create the offset because substr is one-based (+1) and you want to include the space (+1). However, I prefer the regular expression solution even though it probably performs worse because I find it somewhat more self-documenting. It has the additional advantage that it is idempotent: if you run it again on the database it won’t have any effect. The substr/offset method is not idempotent; if you run it again, it will eat more characters off your last name.

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