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Home/ Questions/Q 7017539
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T22:55:38+00:00 2026-05-27T22:55:38+00:00

I’ve this model in SQLAlchemy: class User(Base): __tablename = ‘users’ id = Column(Integer, primary_key=True,

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I’ve this model in SQLAlchemy:

class User(Base):
    __tablename = 'users'
    id = Column(Integer, primary_key=True, autoincrement=True)
    type = Column(Text, nullable=False)
    user_name = Column(Text, unique=True, nullable=False)
    __mapper_args__ = {'polymorphic_on': type}

class Client(User):
    __tablename__ = 'clients'
    __mapper_args__ = {'polymorphic_identity': 'client'}
    id = Column(Integer, ForeignKey('users.id'), primary_key=True)
    client_notes = Column(Text)

This is a joined table inheritance. The problem is when I’m querying User:

self.session.query(User).all()

all I get is records from clients, while what I want is all record on User without Client. How do I solve this problem?

Edit: I’m using SQLAlchemy 0.7.4 and Pyramid 1.3a3

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  1. Editorial Team
    Editorial Team
    2026-05-27T22:55:39+00:00Added an answer on May 27, 2026 at 10:55 pm

    session.query(User) does not perform any filtering based on the value of type column.
    However, the SQL SELECT statement it generates selects only data from the users table (unless with_polymorphic(...) is used).

    But you can add the filter explicitely to achive the desired result:

    session.query(User).filter(User.type=='user').all()
    
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