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Home/ Questions/Q 8102795
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T23:20:04+00:00 2026-06-05T23:20:04+00:00

I’ve tried implementing this example , but the progress never displays. My page doesn’t

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I’ve tried implementing this example, but the progress never displays. My page doesn’t include any UpdatePanels or anything, could that be why?

In my page declaration I’ve added:

<%@ Register Assembly="AjaxControlToolkit" Namespace="AjaxControlToolkit" TagPrefix="ajaxToolkit" %>

Inside the head element I’ve added:

<script src="Scripts/jsUpdateProgress.js" type="text/javascript"></script>

Immediately inside of my form tag I’ve added:

<asp:ScriptManager ID="ScriptManager1" runat="server"></asp:ScriptManager>
<asp:Panel ID="panelUpdateProgress" runat="server" CssClass="updateProgress">
    <asp:UpdateProgress runat="server" ID="UpdateProg1" DisplayAfter="0">
        <ProgressTemplate>
            <div style="position:relative; top:30%; text-align: center;">
                <img src="Processing.gif" style="vertical-align: middle" alt="Processing"/>
                  Processing...
            </div>
        </ProgressTemplate>
    </asp:UpdateProgress>
</asp:Panel>
<ajaxToolkit:ModalPopupExtender runat="server" ID="ModalProgress" TargetControlID="panelUpdateProgress" BackgroundCssClass="modalBackground" PopupControlID="panelUpdateProgress"/>

Immediately following end form tag I’ve added:

<script type="text/javascript">
        Sys.WebForms.PageRequestManager.getInstance().add_beginRequest(beginReq);
        Sys.WebForms.PageRequestManager.getInstance().add_endRequest(endReq);
        var ModelProgress = '<%= ModalProgress.ClientID %>';
        function beginReq(sender, args) {
            $find(ModalProgress).show();
        }            
        function endReq(sender, args) {
            $find(ModalProgress).hide();
        }
</script>

The button I expect to cause the progress to show:

<asp:Button runat="server" ID="submit" CssClass="multiViewTab" Text="Submit"/>

That button definitely posts back because in my form tag I have:

onsubmit="return validateForm()"

And validateForm runs. validateForm also kicks off the submitForm function if the form is valid, and this contains a JQuery call to AJAX invoking a web service.

Take 2:

Much simpler and pure AJAX, but still doesn’t work.

 </form>
 <script type='javascript'>
   $(document).ready(function() {
    $('body').append('<div id="ajaxBusy"><p><img src="Processing.gif"></p></div>');
    $('#ajaxBusy').css("updateProgress");
  });

  $(document).ajaxStart(function () {
            $('#ajaxBusy').css("z-index", 2);
        }).ajaxStop(function () {
            $('#ajaxBusy').css("z-index", -1);
        });

I am using z-index because I have a makeshift “wizard” which in essence shows/hides divs using z-index and the progress div wouldn’t show up if I didn’t change the z-index.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T23:20:05+00:00Added an answer on June 5, 2026 at 11:20 pm

    According to MSDN, the UpdateProgress provides feedback when contents of an UpdatePanel are updated.

    My page doesn’t include any UpdatePanels or anything, could that be
    why?

    In short, yes.

    Source: UpdateProgress Class

    The above link has a nice example.

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