Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6468653
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T05:54:35+00:00 2026-05-25T05:54:35+00:00

I’ve tried to create a new table relation but I seem to have gotten

  • 0

I’ve tried to create a new table relation but I seem to have gotten an error for which I’m not sure why. The first relation (one to many) I made was last week and it works good, maybe I forgot the correct procedure since then?

Simple explanation:
I have three tables – events, music_styles, venues

So far, I correctly linked events and venues in the way that one venue can have multiple events linked to it. I tried making a new table that has rows for each musical style and an ID that would be used in table ‘events’ so that I can link each event to a musical style id.

However this is the error I got:

SQL query:

ALTER TABLE events ADD FOREIGN KEY ( MUSIC_STYLE_ID ) REFERENCES
nightl7_complete.music_styles ( MUSIC_ID ) ON DELETE NO ACTION
ON UPDATE NO ACTION ;

MySQL said: Documentation

1452 – Cannot add or update a child row: a foreign key constraint

fails (nightl7_complete/#sql-2721_c0dcfd, CONSTRAINT
#sql-2721_c0dcfd_ibfk_2 FOREIGN KEY (MUSIC_STYLE_ID) REFERENCES
music_styles (MUSIC_ID) ON DELETE NO ACTION ON UPDATE NO ACTION)
Documentation Error ALTER TABLE events ADD FOREIGN KEY (
MUSIC_STYLE_ID ) REFERENCES nightl7_complete.music_styles (
MUSIC_ID ) ON DELETE NO ACTION ON UPDATE NO ACTION ;

And this is the procedure I did 🙂

enter image description here

I uploaded a full sized image here

Thanks everyone 🙂


Edit:

So I did this:

$query = 'SELECT e.* FROM events e '.
    'LEFT JOIN nightl7_complete.music_styles ms ON ms.ID = e.MUSIC_STYLE_ID'.
    'WHERE ms.id IS NULL';
$result = mysql_query($query);
if (!$result) {
  die('Invalid query: ' . mysql_error());
}

and got this:

Invalid query: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘ms.id IS NULL’ at line 1

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T05:54:35+00:00Added an answer on May 25, 2026 at 5:54 am

    Don’t you want to link MUSIC_STYLE_ID to ID, not MUSIC_ID?

    Also, you need to either pre-populate MUSIC_STYLE_ID with valid ids from music_styles, or set them to null before creating the foreign key.

    To verify this, try:

    SELECT e.*
      FROM events e
      LEFT JOIN nightl7_complete.music_styles ms ON ms.ID = e.MUSIC_STYLE_ID
      WHERE ms.id IS NULL;
    

    If that query returns any records, those are entries in events that don’t contain corresponding records in music_styles

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have just tried to save a simple *.rtf file with some websites and
I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
I have a French site that I want to parse, but am running into
I have a text area in my form which accepts all possible characters from
link Im having trouble converting the html entites into html characters, (&# 8217;) i
I want to count how many characters a certain string has in PHP, but
I am trying to understand how to use SyndicationItem to display feed which is
I used javascript for loading a picture on my website depending on which small
I have a jquery bug and I've been looking for hours now, I can't
Basically, what I'm trying to create is a page of div tags, each has

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.