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Home/ Questions/Q 620281
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:44:46+00:00 2026-05-13T18:44:46+00:00

I’ve tried to implement function composition with nice syntax and here is what I’ve

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I’ve tried to implement function composition with nice syntax and here is what I’ve got:

from functools import partial

class _compfunc(partial):
    def __lshift__(self, y):
        f = lambda *args, **kwargs: self.func(y(*args, **kwargs)) 
        return _compfunc(f)

    def __rshift__(self, y):
        f = lambda *args, **kwargs: y(self.func(*args, **kwargs)) 
        return _compfunc(f)

def composable(f):
    return _compfunc(f)

@composable    
def f1(x):
    return x * 2

@composable
def f2(x):
    return  x + 3

@composable
def f3(x):
    return (-1) * x

print f1(2) #4
print f2(2) #5
print (f1 << f2 << f1)(2) #14
print (f3 >> f2)(2) #1
print (f2 >> f3)(2) #-5

It works fine with integers, but fails on lists/tuples:

@composable
def f4(a):
    a.append(0)

print f4([1, 2]) #None

Where is a mistake?

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  1. Editorial Team
    Editorial Team
    2026-05-13T18:44:47+00:00Added an answer on May 13, 2026 at 6:44 pm

    append does in-place addition, as Ignacio Vazquez-Abrams said (well, implied) — so, while you could fix that by just adding a return to your function, it would have the side-effect of changing the argument it was passed, too:

    @composable
    def f4(a):
        a.append(0)
        return a
    

    It would be best to use the following even more concise code which also creates and returns a new object:

    @composable
    def f4(a):
      return a + [0]
    
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