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Home/ Questions/Q 6364887
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T00:13:20+00:00 2026-05-25T00:13:20+00:00

I’ve written a model loader in C++ an OpenGL. I’ve used std::vector s to

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I’ve written a model loader in C++ an OpenGL. I’ve used std::vectors to store my vertex data, but now I want to pass it to glBufferData(), however the data types are wildly different. I want to know if there’s a way to convert between std::vector to the documented const GLvoid * for glBufferData().

Vertex type

typedef struct
{
    float x, y, z;
    float nx, ny, nz;
    float u, v;
}
Vertex;

vector<Vertex> vertices;

glBufferData() call

glBufferData(GL_ARRAY_BUFFER, vertices.size() * 3 * sizeof(float), vertices, GL_STATIC_DRAW);

I get the following (expected) error:

error: cannot convert ‘std::vector<Vertex>’ to ‘const GLvoid*’ in argument passing

How can I convert the vector to a type compatible with glBufferData()?

NB. I don’t care about correct memory allocation at the moment; vertices.size() * 3 * sizeof(float) will most likely segfault, but I want to solve the type error first.

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  1. Editorial Team
    Editorial Team
    2026-05-25T00:13:21+00:00Added an answer on May 25, 2026 at 12:13 am

    If you have a std::vector<T> v, you may obtain a T* pointing to the start of the contiguous data (which is what OpenGL is after) with the expression &v[0].


    In your case, this means passing a Vertex* to glBufferData:

    glBufferData(
       GL_ARRAY_BUFFER,
       vertices.size() * sizeof(Vertex),
       &vertices[0],
       GL_STATIC_DRAW
    );
    

    Or like this, which is the same:

    glBufferData(
       GL_ARRAY_BUFFER,
       vertices.size() * sizeof(Vertex),
       &vertices.front(),
       GL_STATIC_DRAW
    );
    

    You can rely on implicit conversion from Vertex* to void const* here; that should not pose a problem.

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