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Home/ Questions/Q 875571
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T11:17:31+00:00 2026-05-15T11:17:31+00:00

I’ve written a simple linq query as follows: var query = from c in

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I’ve written a simple linq query as follows:

var query = from c in context.ViewDeliveryClientActualStatus
            join b in context.Booking on c.Booking equals b.Id
            join bg in context.BookingGoods on c.Booking equals bg.BookingId
            select new { c, b, bg };

I have filtered the previous query with a number of premises and then needed to group by a set of fields and get the sum of some of them, as so:

var rows = from a in query
           group a by new {h = a.c.BookingRefex, b = a.c.ClientRefex, c = a.b.PickupCity, d = a.b.PickupPostalCode} into g
           select new
           {                     
               Booking_refex = g.Key.h,
               Client_refex = g.Key.b,
               //Local = g.
               Sum_Quan = g.Sum(p => p.bg.Quantity),
           };

I’d like to get a few values from a which I haven’t included in the group by clause. How can I get those values? They’re not accessible through g.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T11:17:32+00:00Added an answer on May 15, 2026 at 11:17 am

    The g in your LINQ expression is an IEnumerable containing a's with an extra property Key. If you want to access fields of a that are not part of Key you will have to perform some sort of aggregation or selection. If you know that a particular field is the same for all elements in the group you can pick the value of the field from the first element in the group. In this example I assume that c has a field named Value:

    var rows = from a in query
      group a by new {
        h = a.c.BookingRefex,
        b = a.c.ClientRefex,
        c = a.b.PickupCity,
        d = a.b.PickupPostalCode
      } into g
      select new { 
        BookingRefex = g.Key.h, 
        ClientRefex = g.Key.b, 
        SumQuantity = g.Sum(p => p.bg.Quantity),
        Value = g.First().c.Value
      }; 
    

    However, if c.Value is the same within a group you might as well include it in the grouping and access it using g.Key.cValue.

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