Question

I’ve written a very simple code in python and generated one .exe with py2exe.

I’ve added the imports to see if there’s a problem with importing those modules.

import sys
import time, os, httplib2
from csv import writer, reader, DictWriter
from BeautifulSoup import BeautifulSoup

def main():
    print sys.argv[1]

if __name__ == '__main__':
    main()

when I run it as a .py file it works great.

C:\Users\User>C:\Python27\Lib\site-packages\py2exe\samples\sysargv\module3.py
justChecking justChecking

but when I run the executable py2exe had generated it does nothing –

C:\Users\User>C:\Python27\Lib\site-packages\py2exe\samples\sysargv\dist\module3.exe JustCheking

that’s the code of the setup.py

from distutils.core import setup
import py2exe

setup(
    options = {'py2exe': {'bundle_files': 1}},
    windows = [{'script': "module3.py"}],
    zipfile = None,
)

I need to use sys.argv in my program (I’m getting input from the user, things like output directory, log file path etc’)

how do I use sys.argv when using py2exe to create one executable?

another question, if I have python 2.7 32 bit installed on a win7 64 bit computer (I’ve installed the regular win’ 2.7.2 msi file from python.org) and generated a single executable on that computer, will I be able to use the .exe on win7\xp 32 bit?

Thanks

Answer 1

My guess would be that you are using the windows option instead of the console option. That is used for gui apps. If the gui option works, then it would probably spawn a new terminal, which would immediately close once your program is done executing.

You should be able to compile it on windows 7 with 32 bit python and use it on any other 32 bit machine.