Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 620095
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T18:43:35+00:00 2026-05-13T18:43:35+00:00

I’ve written basic jQuery plugins before, but I’m struggling to get my head around

  • 0

I’ve written basic jQuery plugins before, but I’m struggling to get my head around something more complex. I’m looking to emulate the API of jQuery UI, which works like this:

$('#mydiv').sortable({name: 'value'}); // constructor, options
$('#mydiv').sortable("serialize"); // call a method, with existing options
$('#mydiv').sortable('option', 'axis', 'x'); // get an existing option

I’ve tried the following:

(function($){
    $.fn.myPlugin = function(cmd){
        var config = {
            default: 'defaultVal'
        };

        if(typeof cmd === 'object'){
            $.extend(config, cmd);
        }

        function _foo(){
            console.log(config.default);
        }

        if(cmd==='foo'){
            return _foo();
        }

        this.each(function(){
            // do default stuff
        });
    }
})(jQuery);

$('#myElement').myPlugin({default: 'newVal'});
$('#myElement').myPlugin('foo');

What I would like to see here is ‘newval’ being logged, but I’m seeing ‘defaultVal’ instead; the plugin is being called and started from scratch every time I call .myPlugin() on the element.

I’ve also tried using _foo.call(this) and some other variants. No joy.

In a way, I understand why this is happening, but I know that it must be possible to do it the same way as jQuery UI. I just can’t see how!

(I appreciate that jQuery UI uses the widget factory to handle all of this, but I don’t want to make that a requirement for the plugin.)

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T18:43:35+00:00Added an answer on May 13, 2026 at 6:43 pm

    Perhaps what you want is this…

    (function($){
    
        var config = {
            default: 'defaultVal'
        };
    
        $.fn.myPlugin = function(cmd){
    
            if(typeof cmd === 'object'){
                $.extend(config, cmd);
            }
    
            function _foo(){
                console.log(config.default);
            }
    
            if(cmd==='foo'){
                return _foo();
            }
    
            this.each(function(){
                // do default stuff
            });
        }
    })(jQuery);
    
    $('#myElement').myPlugin({default: 'newVal'});
    $('#myElement').myPlugin('foo');
    

    Move the config variable outside the myPlugin function. This change will cause config to be initialized only once: when your plugin function is created.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 386k
  • Answers 386k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer <div id="onee" style="display:none"> header text ..<table> </table></div> <div id="twoo" style="display:none">… May 14, 2026 at 11:42 pm
  • Editorial Team
    Editorial Team added an answer It's not php - you should use var variable_name =… May 14, 2026 at 11:42 pm
  • Editorial Team
    Editorial Team added an answer XPath 2 has a lower-case (and upper-case) string function. That's… May 14, 2026 at 11:42 pm

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.