Question

I’ve written the following, but Java doesn’t like it!

int limit = Math.round(Math.sqrt(inputNumber));

Suggestions from my IDE are to add a cast of (int) to the right hand side, but I was under the impression that Math.round would format the number into an integer anyway?

Answer 1

Math.sqrt(x) returns a double. There are several overloaded Math.round functions. The one that takes a double as the argument returns a long, not an int.