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Home/ Questions/Q 8699713
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T02:01:03+00:00 2026-06-13T02:01:03+00:00

I’ve written the following code to light up a row of LEDs one at

  • 0

I’ve written the following code to light up a row of LEDs one at a time.

int ledPins[] = {7,8,9,10,11,12,13};

void setup() {
  for (int i = 0; i < sizeof(ledPins); i++) {
    pinMode(ledPins[i], OUTPUT);
  }
}

void loop() {
  for (int i = 0; i < sizeof(ledPins); i++) {
    digitalWrite(i, HIGH);
    delay(1000);
    digitalWrite(i, LOW);
    delay(1000);
  }
}

The above works fine. However after completing the for loop there is a long delay (about 10 seconds) before it repeats.

Why would there be such a long delay? Is this expected or is it a problem with my code?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T02:01:05+00:00Added an answer on June 13, 2026 at 2:01 am

    the function sizeof(array) return the size of the array in the memory, in bytes. and because sizeof(int) is probably not 1, you get a larger value than expected.

    sizeof can be use to determine the number of elements in an array, by taking the size of the entire array and dividing it by the size of a single element.

    so this line:

    for (int i = 0; i < sizeof(ledPins); i++) {
    

    should be rewritten as:

    for (int i = 0; i < sizeof(ledPins) / sizeof(int); i++) {
    

    see:
    http://en.wikipedia.org/wiki/Sizeof

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