Question

I’ve written the following which does what I want it to do, but I think there’s a faster way than doing a conditional statement in the for loop.

int i,j,k,l;
int[] X = new int[] {111,222,333,444};
int XL = X.length;

for (i=0, j=1; i<XL; j=(j<XL-1)?j+1:0, i++) {
  println("i:" +i +" j:" + j);
}

// returns:
// i:0 j:1
// i:1 j:2
// i:2 j:3
// i:3 j:0

Answer 1

Kerrek SB’s comment is my preferred solution.
Here it is rewritten to a bit more generic:

String[] X = new String[] {"AAA", "BBB", "CCC", "DDD"};
int XL = X.length;

for (int i=0; i<XL; i++) {
  println("i:" +X[i] +" j:" + X[(i+1)%XL] );
}

will return:

i:AAA j:BBB
i:BBB j:CCC
i:CCC j:DDD
i:DDD j:AAA