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Home/ Questions/Q 9176293
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T17:04:51+00:00 2026-06-17T17:04:51+00:00

I’ve written this code which makes one entry box appear on a new row

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I’ve written this code which makes one entry box appear on a new row when the button is pressed, but I’m not sure how to get it to make a new entry on a new row underneath the last one. My main problems are how to increment a row_number variable within the function without re-setting it every time the function is called, and how to make the function give a new name to the “new_entry” object each time it is called so that it doesn’t overwrite itself.

def new_row():
    #Create widgets   
    new_entry = ttk.Entry(root, width=7)

    #Put widgets in grid
    new_entry.grid(column=0, row=2, sticky=(W, E))

root = Tk()
createRow_button = ttk.Button(root, text='New Row', command=new_row)
createRow_button.grid()

root.mainloop

This is the first time I’ve asked a question on Stack Overflow so sorry if I’ve got anything wrong.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T17:04:52+00:00Added an answer on June 17, 2026 at 5:04 pm

    Use a class and store the number of rows as class attribute, self.num_rows:

    import Tkinter as tk
    
    
    class App(object):
        def new_row(self):
            # Create widgets
            new_entry = tk.Entry(root, width=7)
    
            # Put widgets in grid
            self.num_rows += 1
            new_entry.grid(column=0, row=self.num_rows, sticky='WE')
    
        def __init__(self):
            self.num_rows = 1
            createRow_button = tk.Button(
                root, text='New Row', command=self.new_row)
            createRow_button.grid()
    
    root = tk.Tk()
    app = App()
    root.mainloop()
    
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