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Home/ Questions/Q 841393
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T05:47:16+00:00 2026-05-15T05:47:16+00:00

JAVA NETBEANS // resultsTable, myModel JTable resultsTable; DefaultTableModel myModel; //javax.swing.table.DefaultTableModel myModel = (DefaultTableModel) resultsTable.getModel();

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JAVA
NETBEANS

// resultsTable, myModel
JTable resultsTable;
DefaultTableModel myModel; //javax.swing.table.DefaultTableModel
myModel = (DefaultTableModel) resultsTable.getModel();

// event of clicking on item of table
String value = (String) myModel.getValueAt(resultsTable.getSelectedRow(), columnIndex)

I use JTable and DefaultTableModel to view a table of various info
and I want to get a value of a certain column of the selected index of the table.

The code I wrote above works fine except when:
I use the sort of the GUI (click on the field name I want to sort on the table)
The table is properly sorted but after that when I select a row, it gets
the value of the row that was there before the sort.
This means that after sorting (using the JTable’s GUI)
the ‘myModel’ and ‘resultsTable’ objects have different row indexes.

How do I synchronize those two?

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  1. Editorial Team
    Editorial Team
    2026-05-15T05:47:16+00:00Added an answer on May 15, 2026 at 5:47 am

    You need to use the ‘convertXXX’ methods on the JTable see the JavaDoc

    int row = resultsTable.getSelectedRow();
    if (row != -1) {
       row = table.convertRowIndexToModel(row);
       String value = (String) myModel.getValueAt(row, columnIndex)
    
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