Question

javascript code:

$.getJSON("comprueba_login.php", {usuario:$("#usuario").val(), pwd:$("#contrasena").val()}, function(data){
            alert("resultado: " + data.resultado);
        });

php code:

<?php
    include 'db.php';
    $usuario = $_GET['usuario'];
    $pwd = $_GET['pwd'];
    $sql = "SELECT IDUSUARIO FROM USUARIOS WHERE USERUSUARIO = '" . $usuario . "' AND PWUSUARIO = '" . $pwd . "'";
    $res =  mysql_query($sql, $db) or die("fallo query: " . mysql_error());
    // echo $sql . "<br>";      

    if(mysql_num_rows($res)){?>
        {'resultado':'OK'}
    <?php }else{ ?> 
        {'resultado':'NO_OK'}
    <?php }?>

The alert in the javascript code never appears. What am I doing wrong?

Thanks in advance.

Answer 1

JSON keys and string values MUST be enclosed in " double quotes. Single quotes (') WILL NOT work.